![SOLVED: Consider the sequence xn CO of points in R2 n=] where Xn = (an,bn) such that an =1+ (-1)+1 and bn = 1 + Sl 2n for alln €N. C (a) SOLVED: Consider the sequence xn CO of points in R2 n=] where Xn = (an,bn) such that an =1+ (-1)+1 and bn = 1 + Sl 2n for alln €N. C (a)](https://cdn.numerade.com/ask_images/08a26a90eada406e9443f7778ec6092e.jpg)
SOLVED: Consider the sequence xn CO of points in R2 n=] where Xn = (an,bn) such that an =1+ (-1)+1 and bn = 1 + Sl 2n for alln €N. C (a)
![Goal: Does a series converge or diverge? Lecture 24 – Divergence Test 1 Divergence Test (If a series converges, then sequence converges to 0.) - ppt download Goal: Does a series converge or diverge? Lecture 24 – Divergence Test 1 Divergence Test (If a series converges, then sequence converges to 0.) - ppt download](https://images.slideplayer.com/25/8024376/slides/slide_4.jpg)
Goal: Does a series converge or diverge? Lecture 24 – Divergence Test 1 Divergence Test (If a series converges, then sequence converges to 0.) - ppt download
![I don't understand this explanation for \sum_(n=0)^\infty((-1)^n)/(5n-1)? Why test for convergence/divergence AGAIN, if the Limit Comparison Test confirms that both series are the same? | Socratic I don't understand this explanation for \sum_(n=0)^\infty((-1)^n)/(5n-1)? Why test for convergence/divergence AGAIN, if the Limit Comparison Test confirms that both series are the same? | Socratic](https://useruploads.socratic.org/IJNGAZ1qQGmjuJYFPCa5_lateximg.png)
I don't understand this explanation for \sum_(n=0)^\infty((-1)^n)/(5n-1)? Why test for convergence/divergence AGAIN, if the Limit Comparison Test confirms that both series are the same? | Socratic
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real analysis - Determine if the sequence $\frac{3^n}{n^3+1}$ converges or diverges - Mathematics Stack Exchange
![I don't understand this explanation for \sum_(n=0)^\infty((-1)^n)/(5n-1)? Why test for convergence/divergence AGAIN, if the Limit Comparison Test confirms that both series are the same? | Socratic I don't understand this explanation for \sum_(n=0)^\infty((-1)^n)/(5n-1)? Why test for convergence/divergence AGAIN, if the Limit Comparison Test confirms that both series are the same? | Socratic](https://useruploads.socratic.org/GElC3TZCSVu1KUh19XCf_lateximg.png)